given
[tex] - 3 {x}^{2} + x - 4[/tex]
finding the determinant will tell us how many solutions
the determinant is
[tex] {b}^{2} - 4ac[/tex]
so we have
a=-3
b=1
c=-4
so the determinant is
[tex] {1}^{2} - 4( - 3)( - 4) = 1 - 48 = - 47[/tex]
now we know if d=0 there is 1 real solution if d<0 there are complex solutions and if d>0 there are 2 real solutions.
since d=-47<0 there are no real solutions only complex ones
