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Factor the following:
2 x^2 - 32 y^2
Factor 2 out of 2 x^2 - 32 y^2:
2 (x^2 - 16 y^2)
x^2 - 16 y^2 = x^2 - (4 y)^2:
2 (x^2 - (4 y)^2)
Factor the difference of two squares. x^2 - (4 y)^2 = (x - 4 y) (x + 4 y):
Answer:  2 (x - 4 y) (x + 4 y)
ajeigbeibraheem

The factors of the given algebraic expression are 2(x - 4y) (x + 4y)

What is a factor of an algebraic expression?

The factor(s) of an algebraic expression are those values that if multiplied together, will result in a product of the original value.

From the information given, we have:

= 2x² - 32y²

Let's factorize the above expression;

= 2(x² - 16y²)

= 2(x² - (4y)²)

Using the difference of two squares

x² - (4y)² ⇒(x - 4y) (x+4y)

= 2(x - 4y) (x + 4y)

Learn more about factors here:

https://brainly.com/question/219464

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