kaydeemyladyy
kaydeemyladyy
02-12-2017
Mathematics
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WojtekR
WojtekR
02-12-2017
[tex]\boxed{a_1=0.2}\\\\\\r=\dfrac{-0.06}{0.2}=\boxed{-0.3}[/tex]
so:
[tex]a_n=a_1(r)^{(n-1)}\\\\\boxed{a_n=0.2(-0.3)^{(n-1)}}[/tex]
Answer E.
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