A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed?

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03-11-2017
Mathematics

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A cylinder’s radius is reduced to two-fifths its original size and the height is quadrupled. How has the volume of the cylinder changed?

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Аноним Аноним · Answer 1 · 2017-11-03T13:47:29+01:00

Аноним Аноним

03-11-2017

Let the original volume be pi *r^2* h where r = radius and h = height.

The new volume will be pi *(2/5 r)^2 * 4h = pi*4/25 r^2 4h

pi*4/25r^2 * 4h / pi r^2 h = 4/25 * 4 = 16/25

The volume has been reduced by factor of 16/25.

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