Answer:
[tex]\sf Tan \ P = \dfrac{33}{56}[/tex]
Step-by-step explanation:
Trigonometry ratios:
[tex]\sf Tan \ P = \dfrac{opposite \ side \ of \ \angle P}{adajcent \ side \ of \ \angle P}[/tex]
[tex]\sf =\dfrac{QO}{QP}\\\\\\=\dfrac{33}{56}\\\\\\[/tex]
