Respuesta :

[tex]\bf \lim\limits_{x\to 0}\ \cfrac{sin^3(x)}{5x^3}-4 \\ \quad \\\\ \cfrac{sin^3(x)}{5x^3}-4\implies \cfrac{[sin(x)]^3}{5x^3}-4 \\ \quad \\ \cfrac{[sin(x)]^3}{x^3}\cdot \cfrac{1}{5}-4 \\ \quad \\ thus \\ \quad \\ \lim\limits_{x\to 0}\cfrac{[sin(x)]^3}{x^3}\cdot \lim\limits_{x\to 0}\cfrac{1}{5}-4\qquad \boxed{recall \qquad \lim\limits_{x\to 0} \cfrac{sin(x)}{x}\implies 1} \\ \quad \\ 1\cdot \cfrac{1}{5}-4[/tex]

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