The equation to solve for the width of a rectangular frame that has a total area of 140 square inches is 4x²+32x-80=0.
The area of the rectangle is the product of its length and its breadth.
As it is given that the length of the rectangular frame is (2x+10), while the width of the rectangular frame is (2x+6). Also, it is mentioned that the area of the rectangular frame is 140 in².
Now we know the area is the product of length and breadth, therefore,
[tex]\rm \text{Area of rectangle} = length \times breadth[/tex]
[tex]140 = (2x+10)(2x+6)\\\\140 = 4x^2 + 12x + 20x + 60\\\\0=-140+4x^2 + 12x + 20x + 60\\\\4x^2 + 32 x -80=0[/tex]
Hence, the equation to solve for the width of a rectangular frame that has a total area of 140 square inches is 4x²+32x-80=0.
Learn more about the Area of Rectangle:
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Answer:
A, 4x2 + 32x − 80 = 0
Step-by-step explanation:
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