Respuesta :

mathslover97

Answer:

We know that a(1)=1

a(1)=3*1(1-1)=3*1*0=3*0=0 (any no.multiplied by 0 is equal to 0)

a(2)=3*2(2-1)=3*2*1=6*1=6

Similarly,

a(3)=18

a(4)=36

a(5)=60

Hence, the first five terms of sequence a(n)=3*a(n-1), where a(1)=1 are 0,6,18,36,60.

Thanks for reading.

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