Respuesta :

mhanifa

Answer:

  • x³ = 3x² + 3x - 1
  • x³-  3x² -  3x + 1 = 0
  • (x³ + 1) - 3x(x + 1) = 0
  • (x + 1)(x² - x + 1 - 3x) = 0
  • (x + 1)(x² - 4x + 1) = 0
  • (x + 1)(x² -4x + 4 - 3) = 0
  • (x + 1)((x - 2)² - (√3)²) = 0
  • (x + 1)(x - 2 + √3)(x - 2 - √3) = 0
  • x = -1
  • x = 2 - √3
  • x = 2 + √3