Given:
The expression is
[tex]\sqrt{180m^2}[/tex]
To find:
The value of the given expression by using the perfect squares.
Solution:
We have,
[tex]\sqrt{180m^2}[/tex]
It can be written as
[tex]=\sqrt{2\times 2\times 3\times 3\times 5\times m^2}[/tex]
[tex]=\sqrt{(2)^2(3)^25m^2}[/tex]
[tex]=\sqrt{(2\times 3\times m)^25}[/tex]
[tex]=\sqrt{(6m)^25}[/tex]
[tex]=6m\sqrt{5}[/tex]
Therefore, the value of given expression is [tex]6m\sqrt{5}[/tex].
