Respuesta :

michals7241

Answer:

[tex]9 {x}^{2} - 4 = 0 [/tex]

[tex](3x - 2)(3x + 2) = 0[/tex]

[tex]3x - 2 = 0[/tex]

[tex]3x = 2[/tex]

[tex]x = \frac{2}{3} [/tex]

AND

[tex]3x + 2 = 0[/tex]

[tex]3x = - 2[/tex]

[tex] \times = - \frac{2}{3} [/tex]

Aashutosh

9x²-4=0

or,(3x)² +2*3x*3 +(3)² -5 = 18x -5

or,(3x+3)² = 18x

either,3x+3= 18x or, 3x+3=-18x

or, 15x=3 or, 21x=-3

or, x=1/5 or, x=-1/7