Answer:
x3(x+1)= –2(x-1)–4
3x^2+3x=–2x+2-4
3x^2+3x+2x=2-4
3x^2+5x=–2
3x^2+5x+2=0
3x^2+3x+2x+2=0
3x(x+1)2(x+1)=0
(3x+2)(x+1)=0
3x+2=0 or x+1=0
3x=–2 or x=–1
x=–2/3 or –1
Step-by-step explanation:
–remove brackets by multiplication
–form a quadratic equation
–and then solve either by means of quadratic formula or factorisation method
