Answer:
9. [tex]x=30, y=10\sqrt{3}[/tex]
11. [tex]x=5\sqrt{3}, y=10\sqrt{3}[/tex]
Step-by-step explanation:
9)
[tex]\sin x=\dfrac{10}{20}\\x=\sin^{-1}\left( \dfrac{1}{2} \right)=30^{\circ}\\y=\sqrt{20^2-10^2}=\sqrt{400-100}=\sqrt{300}=10\sqrt{3}[/tex]
11)
[tex]\tan 60= \dfrac{15}{x}\\x=\dfrac{15}{\tan 60}=5\sqrt{3}\\y=\sqrt{(5\sqrt{3})^2+15^2}=\sqrt{75+225}=\sqrt{300}=10\sqrt{3}[/tex]
Hope this helps!
