Answer:
see explanation
Step-by-step explanation:
By the rational root theorem, any rational roots of f(x) are expressible in the form
[tex]\frac{p}{q}[/tex] for integers p and q
with p a divisor of the constant term 6 and q a divisor of the leading coefficient 1.
The possibilities are ± 1, ± 2, ± 3, ± 6
Since the lead coefficient is 1 dividing by that number doesn't change a thing.
Thus the possible rational roots are
[tex]\frac{p}{q}[/tex] = - 6, - 3, - 2, -1, 1, 2, 3, 6
