[tex]{\texttt{\huge{\purple{ANSWER :-}}}}[/tex]
what is the solution to the system below
4x +y=1 and y=6x+1
A no solution
B (0,1) ✔️✔️
C many solution
D. (0,25,0)
[tex] = > \: as \: there \: are \: two \: equations \: which \: follows \: only \: one \: value.[/tex]
Answer:B(0,1)
Explanation:
Using direct substitution, let y be 6x+1
Substitute for y in 4x+y=1
We have 4x+6x+1=1
10x=1-1
10x=0,
x=0.
Substitute 0 for x in y=6x+1
y=6*0+1
the solution is (0,1)
