Answer:
[tex]P =0.857[/tex]
Step-by-step explanation:
We know that 60% of students have an iPad and a car and 70% have a car.
If we call A the event "have an iPad" and call the event B "have a car"
So
[tex]P (A\ and\ B) = 0.6\\\\P(B) = 0.7[/tex]
We look for the probability that a student with a car also has an iPad. This is
[tex]P (A | B) = \frac{P(A\ and\ B)}{P(B)}\\\\P (A | B) = \frac{0.6}{0.7}\\\\P (A | B) = 0.857[/tex]