For this case we have the following equation to find [tex]b_ {1}[/tex]
[tex]b_ {1} = \frac {2A} {h} -b_ {2}\\\\[/tex]
If we want to find an equivalent equation, we do the following:
[tex]\frac{2A}{h}-b_{2}=\frac{2A*1-b_{2}*h}{h}=\frac{2A-b_{2}h}{h}\\\\[/tex]
So, we have to:
[tex]b_ {1} = \frac {2A} {h} -b_ {2} = \frac {2A-b_ {2} h} {h}\\[/tex]
Answer:
Option A
