What is the distance between (5 - 2i) and (8 + i)?

Question

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Respuesta :

skopie skopie · Answer 1 · 2019-02-01T03:52:19+01:00

Answer:

Step-by-step explanation:

In complex plane we can see a+bi as the point (a,b).

so 5-2i can be seen as (5,-2)

and 8+i can be seen as (8,1)

Now we can use the distance formula to find the distance between the two points .

Distance formula is

[tex]D=\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex]

Plugging the respective values we get

[tex]D= \sqrt{((5-8)^2+(-2-1)^2}\\D= \sqrt{(-3)^2+(-3)^2\\[/tex]

[tex]D = \sqrt{9+9} \\D=\sqrt{18} \\D=3\sqrt{2}[/tex]

so Distance is [tex]3\sqrt{2}[/tex]

zainebamir540 zainebamir540 · Answer 2 · 2019-02-01T15:07:24+01:00

Answer:

3√2

Step-by-step explanation:

We have to find distance between two points.

We represent a+bi as (a,b) on graph.

Hence, 5-2i can be represented as (5,-2).

and 8+i can be represented as (8,1).

By using distance formula, we can find distance between two points.

d=[tex]\sqrt{(y_{2}-y_{1} )^{2} +(x_{2} -x_{1} )^{2}}[/tex]

d=[tex]\sqrt{(1-(-2))^{2}+(8-5)^{2}}[/tex]

d=[tex]\sqrt{(3)^{2} +(3)^{2} }[/tex]

d=[tex]\sqrt{9+9}[/tex]

d=[tex]\sqrt{18}[/tex]

d=[tex]\sqrt{9.2}[/tex]

d=3√2 is distance between (5-2i) and (8+i).