The point-slope form:
[tex]y-y_1=m(x-x_1)[/tex]
We have the point (-2, 5) and the slope m = -4. Substitute:
[tex]y-5=-4(x-(-2))[/tex]
[tex]y-5=-4(x+2)[/tex] use distributive property
[tex]y-5=-4x-8[/tex] add 5 to both sides
[tex]y=-4x-3[/tex] add 4x to both sides
[tex]4x+y=-3[/tex]
Answer:
point-slope form: y - 5 = -4(x + 2)
slope-intercept form: y = -4x - 3
standard form: 4x + y = -3
