we are given
[tex] y=\frac{1}{3} x-4 [/tex]...........(1)
[tex] y=-\frac{7}{3} x+4 [/tex]...........(2)
we can plug second equation into first one
[tex] -\frac{7}{3} x+4=\frac{1}{3} x-4 [/tex]
now, we can solve for x
[tex] \frac{7}{3} x+\frac{1}{3} x=4+4 [/tex]
[tex] \frac{8}{3} x=8 [/tex]
[tex] x=8*\frac{3}{8} [/tex]
[tex] x=3 [/tex]
now, we can find y
[tex] y=\frac{1}{3} *3-4 [/tex]
[tex] y=-3 [/tex]
so, we will get solution as
[tex] (x,y)=(3,-3) [/tex].............Answer
