Respuesta :

apologiabiology
square root both sides and don't forget to get the positive and negative roots
x=+/-[tex] \sqrt{160} [/tex]

[tex] \sqrt{160} [/tex]=[tex] \sqrt{16} [/tex] times [tex] \sqrt{10} [/tex]

[tex] \sqrt{16} [/tex]=+/-4
 
answer is
+/-4[tex] \sqrt{10} [/tex]

answer is b




Exvited
[tex]x^2 = 160 \\ \\ x = \pm \sqrt{160} \\ \\ x = \pm 4 \sqrt{10} \\ \\ [/tex]

The final result is: x = ±4 √10 or B.

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